The Speculations used for the design of transistor as an amplifier are:
i) Consider the DC and AC quantities:
1. Both ac and dc quantities are used in amplifier circuits.
2. For both ac and dc currents capital letters are used.
3. For dc quantities subscript will be capital letter (Uppercase).
4. For ac quantities Subscript will be lowercase (Small letters) .
ii) Transistor Amplification :
– Since the collector current is equal to the base current multiplied by the current gain (, a transistor can amplify the current.
The Base current (IB) is very small (comparatively very low) compared to IC and IE.
– So it is clear that, IC is almost equal to IE.
Now we can consider the following circuit for the transistor application
– From the circuit, it is clear that at the input side, an ac voltage Vin¬, is superimposed on the applied dc bias voltage VBB.
– Through the collector resistance, RC, the Dc bias voltage VCC is connected to the collector.
– The ac input voltage can produces an ac base current (at the Base), which will results in a much higher ac collector current than the base current.
– The ac collector current yields to an ac voltage across RC (The collector resistance), will produces an amplified, inverted, reproduction of the ac input voltage in the active region of the transistor.
This internal ac emitter resistance can be denoted (represented) by r’e.
Ie (or) Ic = Vb/ r’e
Vc = Ic*RC , which is the ac collector voltage,
Since Ie ? Ic, the ac collector voltage can be Vc ? IeRC.
Vb = Vin – IbRB, where Vb can be considered as the ac input voltage of the transistor
The transistor ac output voltage can be considered as Vc
– The ratio of Vc to V¬b (Vc /V¬b) can be defined as the ac voltage gain Av, of the above transistor circuit.
ie, Av = Vc/Vb (1)
Now we can Substitute IeRC for Vc and Ie r’e for Vb which will make (1) as
Av = Vc/Vb ? (IeRC)/(Ie r’e) = RC/ r’e (2)
– Thus from (2) it is clear that the amplification depends on the ratio of RC and r’e.
– RC will be always much larger in value than r’e, In other words, the output voltage is larger than the input voltage.
Now we can consider one example for the transistor circuit:
Determine the voltage gain and the ac output voltage for the following circuit if r’e = 120 .
We know that the voltage gain is
Av ? RC/r’e = 1 k /120 = 8.333
Hence the output voltage is
Vout = AvVb = (8.333)*(100 mV) = 0.8333 Vrms